Is Jqka 2 A Straight In Poker
4/13/2022by admin
Big 2 is an implementation of the popular card game Big 2 or Big Two (Choh Dai Di, Da Lao Er, Chinese Poker, Cap Sa, and many other names). Big 2 is very popular throughout China, Hong Kong, Malaysia, Singapore and Taiwan. The game is played by 4 players. The objective of the game is to be the first to get rid of all of your cards. The first player to get rid of all his/her cards wins.
Is Jqka 2 A Straight In Poker Card Game
Question:In a deck w 52 cards, 4 suits, 13#s per suit.
how many ways are there for a straight?
in class we were taught that you do
13-4 to account for not being able to have 10,J,Q,K roll over to the lowest card val such as like Q,K,A,2,3 would not count.
this =9 .
so then you look at your hand as in 5 spaces
_ _ _ _ _
you have 9 choices for the lowest 1st #
9 _ _ _ _
then here is where i get lost:
we have 4 choices for each remaining slot?
9 4 4 4 4
and the final answer is
9 * 4^5.
I don't understand 2 things
1) if we have 4 choices for the remaining 4 slots, why is it not 4^4 ..
2) how can we have 4 choices for each slot?
shouldn't it be
9 4 3 2 1 ?
Situation 1
i feel like with the 9 4 4 4 4
you could pick your first # as 3.
then 2nd # as 2
then 3rd # as 2
then 4th # as 1
then 5th # as 2
Situation 2
lets say this somehow accounted for the inability to pick the same #.
once again
you could pick your first # as 3.
then you have 4 choices for your next # (1,2,4,5)
then 2nd # as 2
then you have 4 choices for your next # (1,4,5,6) what about Ace if it was low... that would be 5#s or take out 6.
then 3rd # as 6
then you have 4 choices for your next # (1, 4,5,7) ?
then 4th # as 1
then you have 4 choices for your next # (A, 4,5,7) ? this doesnt make any sense
then 5th # as 4
congrats.. the hand is now 1,2,3,4,6... doesnt work out?
Situation 3
lets say you can only pick #s within 2 of your current #s
you could pick your first # as 3.
then you have 4 choices for your next # (1,2,4,5)
then 2nd # as 2
then you have 4 choices for your next # (A, 1,4,5)
then 3rd # as Ace
then you have only 3 choices for your next # (1, 4,5 ) because theres nothing lower than A, and 6 would be 3 spaces away from 3 so it violates assumption rule
then 4th # as 1
then you have 1-2 choices for your next # (4, 5) ? this doesnt make any sense
then 5th # as 5
congrats.. the hand is now A,1,2,3,5... doesnt work out? again and we didnt use 4#s per choice
how many ways are there for a straight?
in class we were taught that you do
13-4 to account for not being able to have 10,J,Q,K roll over to the lowest card val such as like Q,K,A,2,3 would not count.
this =9 .
so then you look at your hand as in 5 spaces
_ _ _ _ _
you have 9 choices for the lowest 1st #
9 _ _ _ _
then here is where i get lost:
we have 4 choices for each remaining slot?
9 4 4 4 4
and the final answer is
9 * 4^5.
I don't understand 2 things
1) if we have 4 choices for the remaining 4 slots, why is it not 4^4 ..
2) how can we have 4 choices for each slot?
shouldn't it be
9 4 3 2 1 ?
Situation 1
i feel like with the 9 4 4 4 4
you could pick your first # as 3.
then 2nd # as 2
then 3rd # as 2
then 4th # as 1
then 5th # as 2
Situation 2
lets say this somehow accounted for the inability to pick the same #.
once again
you could pick your first # as 3.
then you have 4 choices for your next # (1,2,4,5)
then 2nd # as 2
then you have 4 choices for your next # (1,4,5,6) what about Ace if it was low... that would be 5#s or take out 6.
then 3rd # as 6
then you have 4 choices for your next # (1, 4,5,7) ?
then 4th # as 1
then you have 4 choices for your next # (A, 4,5,7) ? this doesnt make any sense
then 5th # as 4
congrats.. the hand is now 1,2,3,4,6... doesnt work out?
Situation 3
lets say you can only pick #s within 2 of your current #s
you could pick your first # as 3.
then you have 4 choices for your next # (1,2,4,5)
then 2nd # as 2
then you have 4 choices for your next # (A, 1,4,5)
then 3rd # as Ace
then you have only 3 choices for your next # (1, 4,5 ) because theres nothing lower than A, and 6 would be 3 spaces away from 3 so it violates assumption rule
then 4th # as 1
then you have 1-2 choices for your next # (4, 5) ? this doesnt make any sense
then 5th # as 5
congrats.. the hand is now A,1,2,3,5... doesnt work out? again and we didnt use 4#s per choice
Is Jqka 2 A Straight In Poker Tournaments
- Chinese poker is a card game based on poker hand rankings. It is intended a beginner-friendly game, as only a basic knowledge of poker hand rankings is needed to get started. Additionally, the format allows for frequent unexpected outcomes, so there is a large element of luck involved, therefore a beginner has a good chance of winning in the.
- At the beginning of my poker playing, i lost a game, because i thought JQKA2 is a straight. 5 points 4 years ago.
- Please note that straight either begin with an ace or end with an ace, an ace can be the low card or the high card. (Of course not at the same time.) Thus JeffM's list is correct. And the count is ( displaystyle 10. 4^5=10240 ). I found some poker websites that give the answer as ( displaystyle 10220 ).
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